Question

A sum of 45,000 is to be distributed amongst Not more than 18 students as prize amount in demonitation of 250 1250 , 6250 and 31250 such that there is a least one student getting a prize of each denomination and each student gets exactly one prize.The entire amount has to be distributed .The number of ways this armount can be distributed Is

Answer 1

Answer:

2

Step-by-step explanation:

AT LEAST EACH  PRIZE VALUE  TO BE DISTRIBUTED,

SO

250+1250+6250+31250=39000 (4 STUDENT)

REMAINING:- 6000.

(6250,31250) ELIMINATED

WITH 250 AND 1250 WE CAN DISTRIBUTE IN

=250X +1250Y=6000

=X+5Y=24 OR Y=((24-X)/5)

CASES:-  X TO INCREASES TO 5 FOR EVERY ITERATION

1. X=4 Y=4

2. X=9 Y=3

3. X=14 Y=2

4. X=19 Y=1

5. X=24 Y=0

CASES (3,4,5) BECAUSE NO OF STUDENT EXCEEDED 18,(as 4 student initially  given prizes + obtained value of x and y in each case)

SO 1 AND 2 CASE IS VALID