a sum of ₹450 is in the form of ₹2,5and 10.if the coins of ₹2 are 5times the coins of ₹5 and the total number of coins are 90 find the number of coins of each denomination
Answers
Answer:
let the no. of rs 5 coins be x
& the no. of rs 1 coin be y
& no. of rs 2 coins be 3 x
a.q.t total no. of coins = 160
x + 3x+y = 160
4x + y = 160 eq. 1
again a.q.t total rs = 300
5x + 2(3x) + 1y = 300
11x + y = 300 eq. 2
by elimination method
on subtracting both the equations
4x + y = 160
-11x -y = -300
=-7x =-140
x =20
on putting the the value of x in eq 2
4(20) + y =160
80 + y = 160
y =80
now,
no of rs 2 coins = 3(20)
= 60
no. of rs 5 coins = 20
no. of rs 1 coins=80
By: anjalica, 9 years agoLike
Let the no. of Rs. 5 coins be x
no of Rs. 2 will be 3x
Rs. 1 coin be. 160-3x-x = 160-4x
the amount I have,
from Rs. 2 coins= 3x= 3x2 = 6x
from Rs. 5 coins= x= 5x
from Rs. 1 coin = (160-4x)x1 = 160-4x
Total money Rs.300
6x+5x+160-4x = 300
7x + 160 = 300
7x = 140
x = 20
No. of Rs. 2 Coins = 3x20= 60
No. of Rs. 5 coins = x=20
No. of Re. 1 coin = 160-4x20 =80
And That's The answer !! I learned this concept in class 4th!
By: Vikas, 9 years ago1 like this answer
Given, total value of Rs = Rs 300
Total number of coins = 160
Coins of denomination = Re 1, Rs 2 and Rs 5
Number of Rs 2 coins = 3 x number Rs 5 coins
Let the number of coins of Rs 5 = m
Since, the number coins of Rs 2 is 3 times of the number of coins of Rs 5
Therefore, number of coins of Rs 2 = m x 3 = 3m
Now, Number of coins of Re 1 = Total number of coins – (Number of Rs 5 coins + Number of Rs 2 coins)
Therefore,
Number of coins of Re 1 = 160 – (m + 3m) = 160 – 4m
Total Rs = (Re 1 x Number of Re 1 coins) + (Rs 2 x Number of Rs 2 coins) + (Rs 5 x Number of Rs 5 coins)
⇒ 300 = [1 x (160 – 4m)] + (2 x 3m) + (5 x m)
⇒ 300 = (160 – 4m) + 6m + 5m
⇒ 300 = 160 – 4m + 6m + 5m
⇒ 300 = 160 – 4m + 11m
⇒ 300 = 160 + 7m
After transposing 160 to LHS, we get
300 – 160 = 7m
⇒ 140 = 7 m
After dividing both sides by 7, we get
Solution of exercise 2.2 Linear equations in one variable class eight math25
Thus, number of coins of Rs 5 = 20
Now, since, number of coins of Re 1 = 160 – 4m
Thus, by substituting the value of m, we get
Number of coins of Re 1 = 160 – (4 x 20) = 160 – 80 = 80
Now, number coins of Rs 2 = 3m
Thus, by substituting the value of m, we get
Number of coins of Rs 2 = 3m = 3 x 20 = 60
Therefore,
Number of coins of Re 1 = 80
Number of coins of Rs 2 = 60
Number of coins of Rs 5 = 20
By: 137823, 3 years agoLike
Let the number of 5 coins be x
Acording to the question
The number of ₹2 coins 3x
The number of ₹1 coins =160 -3x - x =160 -4x
The amount I have
From rs 2 coins 3x ×2= 6x
From rs 5 coins 5 × x= 5x
from Rs 1 coins=(160 - 4x)×1= 160 - 4x
6x +5x +160 -4x=300
7x = 300 - 160 = 140
x= 140 ÷ 7=20
The no. of 2 coins =3× 20= 60
The no. of 1 coins =160 - 4x ×20 =80
The no of 5 coins = 20
By , Hardik Sharma
By: RAHUL KUMAR, 2 years agoLike
Let the number of 5 coins be x
Acording to the question
The number of ₹2 coins 3x
The number of ₹1 coins =160 -3x - x =160 -4x
The amount I have
From rs 2 coins 3x ×2= 6x
From rs 5 coins 5 × x= 5x
from Rs 1 coins=(160 - 4x)×1= 160 - 4x
6x +5x +160 -4x=300
7x = 300 - 160 = 140
x= 140 ÷ 7=20
The no. of 2 coins =3× 20= 60
The no. of 1 coins =160 - 4x ×20 =80
The no of 5 coins = 20
By , Hardik Sharma
By: RAHUL KUMAR, 2 years agoLike
Let the number of 5 coins be x
Acording to the question
The number of ₹2 coins 3x
The number of ₹1 coins =160 -3x - x =160 -4x
The amount I have
From rs 2 coins 3x ×2= 6x
From rs 5 coins 5 × x= 5x
from Rs 1 coins=(160 - 4x)×1= 160 - 4x
6x +5x +160 -4x=300
7x = 300 - 160 = 140
x= 140 ÷ 7=20
The no. of 2 coins =3× 20= 60
The no. of 1 coins =160 - 4x ×20 =80
The no of 5 coins = 20
By , Hardik Sharma
By: RAHUL KUMAR, 2 years ago1 like this answer
Let the number of 5 coins be x
Acording to the question
The number of ₹2 coins 3x
The number of ₹1 coins =160 -3x - x =160 -4x
The amount I have
From rs 2 coins 3x ×2= 6x
From rs 5 coins 5 × x= 5x
from Rs 1 coins=(160 - 4x)×1= 160 - 4x
6x +5x +160 -4x=300
7x = 300 - 160 = 140
x= 140 ÷ 7=20
The no. of 2 coins =3× 20= 60
The no. of 1 coins =160 - 4x ×20 =80
The no of 5 coins = 20
By , Hardik Sharma
By: RAHUL KUMAR, 2 years ago1 like this answer
Let the number of 5 coins be x
Acording to the question
The number of ₹2 coins 3x
The number of ₹1 coins =160 -3x - x =160 -4x
The amount I have
From rs 2 coins 3x ×2= 6x
From rs 5 coins 5 × x= 5x
from Rs 1 coins=(160 - 4x)×1= 160 - 4x
6x +5x +160 -4x=300
7x = 300 - 160 = 140
x= 140 ÷ 7=20
The no. of 2 coins =3× 20= 60
The no. of 1 coins =160 - 4x ×20 =80
The no of 5 coins = 20
By , Hardik Sharma
By: RAHUL KUMAR, 2 years ago1 like this answer
Let the number of 5 coins be x
Acording to the question
The number of ₹2 coins 3x
The number of ₹1 coins =160 -3x - x =160 -4x
The amount I have
From rs 2 coins 3x ×2= 6x
From rs 5 coins 5 × x= 5x
from Rs 1 coins=(160 - 4x)×1= 160 - 4x
6x +5x +160 -4x=300