A sum of $500 is in the form of
denominations of $5 and $10. If the total
number of notes is 90
find the
number
of
notes of each denomination?
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Answer:
let the number of $5notes be x and $10notes be y
so, x+y=90 => -5x-5y= -450 ..............(1)
valve of notes is 5x+10y=500..................(2)
add (2)+(1)
=> 5x+10y-5x-5y=500-450
=> 5y=50 => y=10
so, x=80
SO NO: OF
- $5 NOTES IS 80
- $10 NOTES IS 10
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