Question

A sum of 500 is in the form of denominations of 75 and 10. If the total number of notes is
90, find the number of notes of each type.
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Answer 1

$\bigstar \underline{\underline{\sf Correct\ Question:-}}$

❥ A sum of 500 is in the form of denominations of Rs.5 and 10. If the total number of notes is  90, find the number of notes of each type.

$\bigstar \underline{\underline{\sf Answer:-}}$

$\bigstar \bf Given:-$

• A sum of 500 is in the form of denominations of Rs.5 and 10.
• Total no of notes = 90.

$\bigstar \bf To\ find:-$

• No of notes of each type.

$\bigstar \bf Solution:-$

Let, no of Rs.5 notes are 'x'.

Give,Total number of notes = 90

Hence,The no of Rs.10 notes are (90 − x)

According to question,

Total sum of money = Rs 500

=>  5x + 10 (90 − x) = 500

=> 5x + 900 − 10x = 500

=>  − 5x = 500 − 900

=> -5x = −400

=> x = 80

Therefore, there are 80 notes of Rs.5 .

so,

Number of Rs 10 notes = 90 - 80 = 10

Hence there are 10 notes of Rs 10.

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HOPE IT HELPS !

Answer 2

Answer:

$\huge\rm{Question}$

1) A sum of 500 is in the form of denominations of Rs 5 and Rs 10. If the total number of notes is 90, find the number of notes of each type.

$\huge\rm{Solution:–}$

$\rm {\: ❥ \: Let \: the \: {number \: of \: 5 \: rupees \: note \: be \: \: x}} \\ \rm \: ❥ \: 10 \: rupees \: note \: = \: (90-x)$

$\rm \: →5x+10(90-x)=500 \\ \rm \: →5x+900-10x=500 \\ \rm \: →-5x=500-900 \\ \rm \: →-5x=-400 \\ \rm \: →x= \frac{-400}{+5} \\ {\fbox{x = 30}}$

Hence no.of 5 rupees note is 80

No of 10 rupees notes = 90-x

= 90-80

= 10

Hence no of 10 rupees notes is 10