Question

A sum of 500 is in the form of notes of denominations of 35 and 10. If the total number of notes is 90, find the number of notes of each type​

Answer 1

Answer:

Let the number of ₹ 5 notes = x

∴ The number of ₹10 notes = 90-x

Value of ₹ 5 notes= x \times₹5 = ₹ 5x

an the value of ₹10 notes = (90-x)\times₹10 = ₹(900-10x)

∴The total value of all the notes = ₹500

∴5x+(900-10x)=500

⇒5x+900-10x=500

⇒-5x=500-900

⇒-5x=-400

⇒x=\frac{-400}{-5}

⇒x=80

∴ The number of ₹ 5 notes = x = 80 and

The number of ₹ 10 notes = 90-x = 90-80 = 10 .

Step-by-step explanation:

Answer 2

Given: A sum of $500$is in the form of notes of denominations of$35 and 10$ and the total number of notes is$90$.

We have to find the number of notes of each type​.

We are solving in the following way:

Let the number of $5$rupee notes be$x$, then

The number of $10$rupee notes $=90-x$

$\begin{array}{l}=>5 x+10(90-x)=500 \\=>5 x+900-10 x=500\\=>5x-10x=500-900 \\=>5 x=400 \\=>x=80\end{array}$

There are $80$notes of Rs.$5$ and

=>$(90-80)=10$

$10$notes of Rs.$10$

Hence, there are $80$notes of Rs.$5$ and $10$notes of Rs.$10$

Note:

The question is wrong it should be:

Q. A sum of Rs.500 is in the form of denominations of Rs.5 and Rs.10. If the total number of notes is 90 find the number of notes of each denomination.