a sum of 500 rs denominations of 5rs and 10 rs. if the total number of notes is 90 find the number of notes of each denomination.
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Let the total no of 5 Rs notes be x and 10 Rs notes be y
x+y = 90......(1)
5x+10y = 500.....(2)
Multiplying eq (1) by 10
10x+10y = 900......(3)
Subtracting eq (2) from eq (3)
After calculation,
5x = 400
x = 80
Substituting x = 80 in eq (1)
x+y = 90
80+y = 90
y = 10
Therefore, No of 5 Rs notes is 80 and no of 10 Rs notes is 10
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Answer:
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Step-by-step explanation:
Total sum = 500
Let number of 5 rupees note be x and that of 10 be y
Total notes = 90
value of 5 and 10 rupee note be 5x and 10y
According to the question
X+y=90
y=90-x.....1
And 5x+10y=500
x+2y=100.......2
Put 1 in 2
x+180-2x=100
-x=-80
x=80
Therefore if put in 1 y = 10
So we have 400 ruppes of 5 rupee note and 100 of 10 rupess note
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