Question

A sum of ₹5640 is divided among P,Q and R in the ratio 13:16:18. How much amount did R get more than P

Answer 1

600.
Let the coommon multiple be x
Therefore, nos are 13x, 16x, 18x,
Therefore, 13x+16x+18x=47x
5640÷47x
Therefore, x=120
Therefore , 18x - 13x =5x
5 × 120= 600

Answer 2

let k be the factor
then
13k+16k+18k=5640
k(13+16+18)=5640
k(47)=5640
k=120
:-amount P = 13*120=1560
:-amount Q =16*120=1920
:-amount R =18*120=2160
:-The amount of money R get more than P = 2160-1560=600
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