A sum of 6240 is spread over 30 instalments , each instalment is rupees 10 more the preceding instalment . Calculate the first instalment
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Answered by
2
Sum of 30 installments=6240
n=30. d=10. S=6240
S=n/2{2a+(n-1)d}
6240=15{2a+14d}
a+7d=6240/30
a+7d=208
a+70=208
a=138
Hence, the first installment is RS.138
zen900:
wrong... it will be 29d
Oh I'm sorry for it. And thank you Mr.Zen for rectifying it.
Answered by
2
Let each installment be x rupees
Installments are in a. P. So,
6240=30/2(2x + 290)
==>2x + 290=6240/15
=>2x =416-290
=>2x=126
=>x=63
So first installment is rupees 63.hope this helps
Installments are in a. P. So,
6240=30/2(2x + 290)
==>2x + 290=6240/15
=>2x =416-290
=>2x=126
=>x=63
So first installment is rupees 63.hope this helps
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