Question

a sum of 8.85 is made up of 124 coins sum of which are 10 paise coin and rest are 5 paise coin how many are there of each

Answer 1

$\textbf{Answer}$

Suppose number of 10 paise coin is x

$\textbf{Since total coins are 124,}$

Number of 5 paise coin = (124 - x)

Since value of one coin of 10 paise is 10,
&
Value of one coin of 5 paise is 5.

=> Total value of both coins = 10(x) + 5(124 - x)

$\textbf{Total value of both coins = 885 paise}$

$\textbf{According to the question,}$

10(x) + 5(124 - x) = 885

=> 10x - 5x + 620 = 885

=> 5x = 885 - 620

=> 5x = 265

=> x = 265/5

=> x = 53

=> 124 - x = 124 - 53 = 71

$\textbf{Lets verify value of x,}$
If x = 53,
Value of 10 paise coin = 10x = 530 paise
Value of 5 paise coin = 5(71) = 355 paise
So total value = 530+355 = 885 paise
$\textbf{Hence Verified}$

$\textbf{Number of 10 paise coin = 53}$
$\textbf{Number of 5 paise coin = 71}$

$\textbf{Hope My Answer Helped}$
$\textbf{Thanks}$

Answer 2

Suppose number of 10 paise coin is x

\textbf{Since total coins are 124,}Since total coins are 124, 

Number of 5 paise coin = (124 - x)

Since value of one coin of 10 paise is 10,
&
Value of one coin of 5 paise is 5.

=> Total value of both coins = 10(x) + 5(124 - x)

\textbf{Total value of both coins = 885 paise}Total value of both coins = 885 paise

\textbf{According to the question,}According to the question, 

10(x) + 5(124 - x) = 885

=> 10x - 5x + 620 = 885

=> 5x = 885 - 620

=> 5x = 265

=> x = 265/5

=> x = 53

=> 124 - x = 124 - 53 = 71

\textbf{Lets verify value of x,}Lets verify value of x, 
If x = 53,
Value of 10 paise coin = 10x = 530 paise
Value of 5 paise coin = 5(71) = 355 paise
So total value = 530+355 = 885 paise
\textbf{Hence Verified}Hence Verified 

\textbf{Number of 10 paise coin = 53}Number of 10 paise coin = 53 
\textbf{Number of 5 paise coin = 71}Number of 5 paise coin = 71