Question

A sum of ₹800 is in denominations of ₹10 and ₹20 if the total. Number of notes is 50,find the number of notes of each type Please answer in steps

Answer 1

let the number of $10 coins be x

then number of $20 coins = 50-x (as total no of coins 50)

amount from $10 coins =$(10*x) = $10x

amount from $20 coins = $(20 * (50 -x)) =$(1000 - 20x)

total amount = $800

= 10x + 1000 - 20x = 800

=  1000 - 10x = 800

= 1000 - 800 = 10x

= 200 = 10x

= x= 200/10

x= 20

thus, no of $10 coins = 20

no of $20 coins =50-20 =30

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Answer 2

Let the number of 10 rupee notes be x and 20 rupee notes be y.

(i)

Given that Number of notes is 50.

⇒ x + y = 50

⇒ x = 50 - y.

(ii)

Given that A sum of 800 is in denomination of 10 and 20 in total.

⇒ 10x + 20y = 800

⇒ 10(50 - y) + 20y = 800

⇒ 500 - 10y + 20y = 800

⇒ 500 + 10y = 800

⇒ 10y = 300

⇒ y = 30.

Substitute y = 30 in (i), we get

⇒ x = 50 - 30

⇒ x = 20.

Therefore:

⇒ Number of notes of rs.10 = 20.

⇒ Number of notes of rs.20 = 30.

Hope it helps!