A sum of ₹800 is in the form of denominations of ₹10 and ₹20. If the total number of notes is 50, find the number of notes of each type
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Let 10 rupees note be equal to x and 20 rupees note be equal to y.
According to the question
10x + 20y = 800 and
x + y = 50
therefore x = 50 - y
substituting value of x
10(50-y) + 20y = 800
500 - 10y + 20y = 800
10y = 800 - 500
therefore y = 30
and x = 20
Thus there are 30 notes of 20 rupees and 20 notes of rupees 10.
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