Question

a sum of ₹800 is in the form of denominations of ₹10 and ₹20. if the total numbers of note is 50, find the number of notes of each type.

Answer 1

Answer:

20 Ten Rs notes and 30 Twenty Rs notes.

Step-by-step explanation:

Let the number of 10 Rs note be=x

number of 20 Rs note be=y

x+y=50→α

10x+20y=800

10(x+2y)=800

x+2y=80→β

β-α→x+2y=80

(-)    x+y=50

y=30

x+y=50

x+30=50

x=50-30

x=20

So 20 Ten Rs notes and 30 Twenty Rs notes...

Answer 2

20 notes of Rs 10

and 30 notes of Rs 20.

Step-by-step explanation:

Given :

Sum = Rs. 800

Denominations of = Rs. 10 and Rs. 20.

Total notes = 50

To find :

Number of each type of notes

Solution :

Let y denote = Rs 10.

Total notes = 50.

Number of notes of Rs 20 = (50 – y)

Total sum of money = Rs 800

⇒ 10y+ 20 (50 – y) = 800

⇒ 10y+ 1000 – 20y= 800

⇒ – 10y = 800 – 1000

⇒ – 10y= – 200

⇒ y = 20

Rs. 10 notes = 20

Rs. 20 notes -

⇒ 50 – y

⇒ 50 – 20

⇒ 30

Therefore,

20 notes of Rs 10 and 30 notes of Rs 20