Math, asked by Pranahu, 1 year ago

a sum of 800 is in the form of denominations of rupees 10 and rupees 20 if total number of note is 50 find the number of notes in its type

Answers

Answered by rmsundaram36
22
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Answered by muakanshakya
73
\Huge\textbf{\underline{Solution:-}}

Answer :-No of 20 Rs Note = 30

No of 10 Rs note = 20 .

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\Large\textbf{Step\:Wise\:Explanation}

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\huge{\red{\bf{\boxed{Step 1:}}}}

Let the no of 10 Rs note be x and no of 20 Rs note be y

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\huge{\green{\bf{\boxed{Step 2:}}}}

So, Now the Equation for 10 and 20 Rs notes

\Large{\bf{\boxed{10x+20y=800}}}.........1)

We got 1st Equation from here.

______________________________↓

\huge{\red{\bf{\boxed{Step 3:}}}}

Now,

According To ques

Total No of Notes = 50
\huge{\bf{\boxed{x+y=50}}}......2)

We got 2nd equation from
Here.

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_________________↓

\huge{\blue{\bf{\boxed{Step 4:}}}}

★Now, MULTIPLY second equation by 10.

★Hence the new equation becomes ,

\huge{\boxed{\bf{10x+10y=800}}}...3)

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\huge{\pink{\bf{\boxed{Step 5:}}}}

★Subtract equation 3rd from 1st.

10x̸ + 20y = 800
10x̸. + 10y = 500
-. -. =. -
____________

10y = 300

[y= 30]

\Large{\boxed{No\:Of\:20\:Rs\: Notes=30}}

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\huge{\red{\bf{\boxed{Step 6:}}}}

Now, Substitute the value of yin 2nd equation to find the value of x I.e no of 10 Rs. notes.

\huge{\boxed{\bf{x+y=50}}}......2)

x + 30 = 50

x = 50 -30= 20

\Large{\boxed{No\:Of\:10\:Rs\: Notes=20}}

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\Huge\textbf{Thanks :)}

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