Question

A sum of 800 rupees is in the form of denominations of 10 rupees and 20 rupees if the total number of notes is 50 find the number of notes of each type

Answer 1

let the total no. of 10 rupees notes be x
no. of 20 rupees notes = 50-x
value of 10 rupees notes = 10x
value of 20 rupees notes = 20(50-x) = 1000-20x
total amount = 10x + 1000 - 20x
.•. 10x+1000-20x = 800
-10x+1000 = 800
1000-800 = 10x
200/10 = x
x = 20
.•. no. of 10 rupees notes = 20
no. of 20 rupees notes = 50-20 = 30

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Answer 2

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$\huge{\underline{\underline{\sf{\blue{SOLUTION:-}}}}}$

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$\sf{\underline{\green{AnswEr:-}}}$

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• Number of 10 rupees notes = 20

• Number of 20 rupees notes = 30

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$\sf{\underline{\green{Given:-}}}$

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• A sum of 800 rupees is in the form of denominations of 10 rupees and 20 rupees. if the total number of notes is 50.

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$\sf{\underline{\green{Find:-}}}$

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• Number of 10 rupees notes = ?

• Number of 20 rupees notes = ?

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$\sf{\underline{\green{Explanation:-}}}$

Let the number of 10 rupees note be y.

$\:\:\:\:\dag\bf{\underline{\underline \red{Then:-}}}$

• 20 rupees note = 50 - y

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$\sf{\underline\pink{A.T.Q:-}}$

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$\longrightarrow \sf {10 \times y + (50 - y) \times 20 = 800}$

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$\longrightarrow \sf {10y + 1000 - 20y = 800}$

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$\longrightarrow \sf {-10y = 800 - 1000}$

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$\longrightarrow \sf {-10y = -200}$

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$\longrightarrow \sf {y = \cancel\dfrac{200}{10} }$

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$\longrightarrow \sf {y = 20}$

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$\:\:\:\:\dag\bf{\underline{\underline \red{Hence:-}}}$

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• Number of 10 rupees notes = 20

• Number of 20 rupees notes = 50 - 20
• Number of 20 rupees notes = 30

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$\rule{200}{2}$