Question

A sum of ages of 5 childrens born at interval of 3 years each is 50. what is tge age of the youngest child

Answer 1

Let the five ages be :-
x,(x+3),(x+6),(x+9) and (x+12)

Given that their sum is 50
________________________

x+x+3+x+6+x+9+x+12 = 50 

5x + 30 = 50 

5x = 50-30

5x = 20

x = 20/5

x = 4

Now,

Age of Youngest child is x $i.e.$ 4 years 



i hope this will help you


-by ABHAY

Answer 2

Hi Mate !!

Here's ur ans :-


Let the age of first child be a

then, the other children's age will be following to it by the interval of 3 years.

a , ( a + 3 ) , ( a + 6 ) , ( a + 9 ) , ( a + 12 )

• The sum of their age is 50

a + a + 3 + a + 6 + a + 9 + a + 12 = 50

5a + 30 = 50

5a = 50 - 30

5a = 20

a = 4

The age of 1st child is ( a ) = 4 years
second child :- ( a + 3 ) = 7 years
Third child :- ( a + 6 ) = 10 years
Fourth child :- ( a + 9 ) = 13 years
Fifth Child :- ( a + 12 ) = 16 years