A sum of ages of 5 childrens born at interval of 3 years each is 50. what is tge age of the youngest child
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Answered by
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Let the five ages be :-
x,(x+3),(x+6),(x+9) and (x+12)
Given that their sum is 50
________________________
x+x+3+x+6+x+9+x+12 = 50
5x + 30 = 50
5x = 50-30
5x = 20
x = 20/5
x = 4
Now,
Age of Youngest child is x
4 years
i hope this will help you
-by ABHAY
x,(x+3),(x+6),(x+9) and (x+12)
Given that their sum is 50
________________________
x+x+3+x+6+x+9+x+12 = 50
5x + 30 = 50
5x = 50-30
5x = 20
x = 20/5
x = 4
Now,
Age of Youngest child is x
i hope this will help you
-by ABHAY
Answered by
1
Hi Mate !!
Here's ur ans :-
Let the age of first child be a
then, the other children's age will be following to it by the interval of 3 years.
a , ( a + 3 ) , ( a + 6 ) , ( a + 9 ) , ( a + 12 )
• The sum of their age is 50
a + a + 3 + a + 6 + a + 9 + a + 12 = 50
5a + 30 = 50
5a = 50 - 30
5a = 20
a = 4
The age of 1st child is ( a ) = 4 years
second child :- ( a + 3 ) = 7 years
Third child :- ( a + 6 ) = 10 years
Fourth child :- ( a + 9 ) = 13 years
Fifth Child :- ( a + 12 ) = 16 years
Here's ur ans :-
Let the age of first child be a
then, the other children's age will be following to it by the interval of 3 years.
a , ( a + 3 ) , ( a + 6 ) , ( a + 9 ) , ( a + 12 )
• The sum of their age is 50
a + a + 3 + a + 6 + a + 9 + a + 12 = 50
5a + 30 = 50
5a = 50 - 30
5a = 20
a = 4
The age of 1st child is ( a ) = 4 years
second child :- ( a + 3 ) = 7 years
Third child :- ( a + 6 ) = 10 years
Fourth child :- ( a + 9 ) = 13 years
Fifth Child :- ( a + 12 ) = 16 years
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