Question

A sum of money amounts to rs.28,000 in 2 years at 20℅ simple interest per annum. Find the sum​

Answer 1

Step-by-step explanation:

p×r×t/100

$\frac{28000 \times 2 \times 20}{100}$

$= 11200$

Answer 2

Answer:

Required sum of money is 20000 rupees.

Step-by-step explanation:

Given,sum of money amounts to rs.28,000 in 2 years at 20℅.

So, amount $= 28000 \: rupees$

and rate of interest $= 20\%$

and time $= 2 \: years$

Here we want to find sum of money.

We know by simple interest rule,

Amount $= \frac{prt}{100} + p$

where p is principal,r is rate of interest and t is time.

Here,

$r = 20\% \\ t = 2 \: years$

So,

$28000 = \frac{p \times 20 \times 2}{100} + p \\ \frac{p \times2 }{5} + p = 28000 \\ \frac{2p}{5} + p = 28000 \\ \frac{2p + 5p}{5} = 28000 \\ \frac{7p}{5} = 28000 \\ 7p = 28000 \times 5 \\ p = \frac{28000 \times 5}{7} \\ p = 4000 \times 5 \\ p = 20000$

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