Question

A sum of money amounts to Rs. 6690 after 3 years and to Rs. 10,035 after 6 years on compound interest .Find the sum,

Answer 1

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Answer 2

Answer:

Let R be the interest rate, A be the initial amount.

Let R be the interest rate, A be the initial amount.Now, we have

Let R be the interest rate, A be the initial amount.Now, we have(1) A X ((100+R) /100 )^ 3 =6690.

Let R be the interest rate, A be the initial amount.Now, we have(1) A X ((100+R) /100 )^ 3 =6690.The amount of 6690 becomes 10035 at R after 3 years.

Let R be the interest rate, A be the initial amount.Now, we have(1) A X ((100+R) /100 )^ 3 =6690.The amount of 6690 becomes 10035 at R after 3 years.Hence,

Let R be the interest rate, A be the initial amount.Now, we have(1) A X ((100+R) /100 )^ 3 =6690.The amount of 6690 becomes 10035 at R after 3 years.Hence,(2) 6690 X ((100 + R) /100) ^ 3 =10035

Let R be the interest rate, A be the initial amount.Now, we have(1) A X ((100+R) /100 )^ 3 =6690.The amount of 6690 becomes 10035 at R after 3 years.Hence,(2) 6690 X ((100 + R) /100) ^ 3 =10035(2) ÷(1) is

Let R be the interest rate, A be the initial amount.Now, we have(1) A X ((100+R) /100 )^ 3 =6690.The amount of 6690 becomes 10035 at R after 3 years.Hence,(2) 6690 X ((100 + R) /100) ^ 3 =10035(2) ÷(1) is((100+ R)/100)^ 3 = 10035 / 6690 = 1.5.

Let R be the interest rate, A be the initial amount.Now, we have(1) A X ((100+R) /100 )^ 3 =6690.The amount of 6690 becomes 10035 at R after 3 years.Hence,(2) 6690 X ((100 + R) /100) ^ 3 =10035(2) ÷(1) is((100+ R)/100)^ 3 = 10035 / 6690 = 1.5.Substituting the value 1.5 in (1),

Let R be the interest rate, A be the initial amount.Now, we have(1) A X ((100+R) /100 )^ 3 =6690.The amount of 6690 becomes 10035 at R after 3 years.Hence,(2) 6690 X ((100 + R) /100) ^ 3 =10035(2) ÷(1) is((100+ R)/100)^ 3 = 10035 / 6690 = 1.5.Substituting the value 1.5 in (1),A X 1.5 = 6690.

Let R be the interest rate, A be the initial amount.Now, we have(1) A X ((100+R) /100 )^ 3 =6690.The amount of 6690 becomes 10035 at R after 3 years.Hence,(2) 6690 X ((100 + R) /100) ^ 3 =10035(2) ÷(1) is((100+ R)/100)^ 3 = 10035 / 6690 = 1.5.Substituting the value 1.5 in (1),A X 1.5 = 6690.A = 6690/ 1.5 = 4460.

Step-by-step explanation:

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