a sum of money at a certain rate per annum of simple interest doubles in 5 years and at a different rate triples in 12 years then find the lower rate of interest per annum
Answers
Lets assume the principal is $ 1
Case 1
Maturity Amount = Principal * ( 1+r/100)^n
(1+r/100)^n = Maturity Amount/Principal
(1+r/100)^5 = 2
n=5 years
Maturity is double of principal. (2/1=2)
^ means - to the power of
(1+r/100)= 5th Root of 2 (use a calculator or excel formula 2^(1/5))
1+(r/100) = 1.1487
r/100= 1.1487–1 = 0.1487
r=14.87% (annual compunded)
Case 2
Maturity Amount = Principal * ( 1+r/100)^n
(1+r/100)^n = Maturity Amount/Principal
(1+r/100)^12 = 3
n=12 years
Maturity is triple of principal. (3/1=3)
(1+r/100)= 12th Root of 3 (use a calculator or excel forumula 12^(1/12))
1+(r/100) = 1.0959
r/100= 1.0959–1 = 0.0959
r=9.59% (annual compunded)
The lower one is 9.59%.
(n - 1) x 100 = r t
(2 - 1) x 100 = 5r
=> r = 20%
(3 - 1) x 100 = 12r
=> r = 200/12
= 16
= 2/3%
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