Math, asked by neelampatel8887, 1 day ago

A sum of money at simple interest double itself in 8 year 4 month . In how much time will it trouble itself?​

Answers

Answered by ParikshitPulliwar
0

Answer: Let the sum be Rs. x. Then, amount = Rs 2x

∴ SI = Rs (2x - x) = Rs x

        Time = 8 whole 4/12 years = 25/3 years

Thus, P = Rs x, SI = Rs x and T = 25/3 years

∴rate = 100*SI/P*T = (100*x/x *3/5) % p.a. = 12% p.a.

Again, sum = Rs x, amount = Rs 3x and rate = 12% p.a.

Then, SI= Rs (3x-x) = Rs 2x

∴P= Rs x, SI = Rs 2x and R = 12% p.a.

∴ Time = 100*SI/P*R

= (100*2x/x*12) years = 50/2 years = 16 years and 8 months.

Hence, the sum will treble itself in 16 years and 8 months

Step-by-step explanation:

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