Question

A sum of money at simple interest doubles itself in 4 years in how much time will it triple itself

Answer 1

Answer: 8years, R=25%

Explanation:p =100, A=200 T=4year

SI=A-P=200-100=100

T=SI×100/P×T

100×100/100×4=50%,

R=25%

P=100, let A=300

SI=A-P=300-100=200

T=SI×100/P×R=200×100/100×25=8 Year

Answer 2

A sum of money at simple interest doubles itself in 4 years in 8 years it will triple itself.

Given:

A sum of money at simple interest doubles itself in 4 years.

To find:

The time at which it becomes triple.

Solution:

We know that simple interest = S.I. = (P*R*T)/100.

Where, P = Principle amount

            R = Rate of interest

            T = Time.

and A = P + S.I.

given that A = 2P

now,

S.I. = A - P

     = 2P- P

     = P

NOW, S.I. = (P*R*4)/100

                =(P*R)/25

 P = (P*R)/25

 R = 25.

If A = 3P,

then, S.I. = 3P-P

               = 2P

 Here, S.I. = (P*R*T)/100

                 = (P*25*T)/100

From above,

2P = (P*T)/4

T = 4*2

T = 8 YEARS

A sum of money at simple interest doubles itself in 4 years in 8 years it will triple itself.

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