Math, asked by avyukt2141, 8 months ago

a sum of money at simple interest doubles itself in 8 years and 4 months. In how many years will it triple itself ?​

Answers

Answered by AbbasMaths
5

Answer:

25 Years

Step-by-step explanation:

This is so becoz,

when T = 8 years 4 months = 8 + 1 / 3 years = 25 / 3 years , then at a rate of R % , the principle doubles itself . This means that intrest is equal to principle , thats why in a given time and rate , it doubles itself ,

Hence ,

SI = PRT / 100

but , SI = P ,

Hence , P = PRT / 100

Hence , 1 = R × T / 100 ( P cancels each other )

Now , T = 25 / 3 years (given ) ,

So , R = 100 × 3 / 25

= 12 %

Hence , R = 12 % .

Now , R = 12 %

P = P

T = ?

SI = 2P ( becoz Principle have to triple itself , so intrest must be 2P , so that amount should be P + 2P = 3P)

Now ,

3P = PRT / 100

P cancels out each other from both side ,

hence ,

3 = R × T / 100

but , R = 12 % , hence

3 = 12 × T / 100 ;

12T / 100 = 3 ;

T = 300 / 12 ;

hence , T = 75 / 3 years

T = 25 years .

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