a sum of money become 3 times in 3 years at compound interest in how many years it becomes 8 times?
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Answer:
Step-by-step explanation:
S = P x (1+I)^n
In first case S = 3 P = P x (1+I)^6
Or (1+I)^6 = 3
In second case
S = P x (1+I)^n
S = 81 P = P x (1+I)^n
81/3 = (1+I)^n / (1+I)^6
(1+I)^(n-6) = 27
n = 24
In 24 years, the sum at end will become 81 times the original sum.———————————————————
Let sum at start be 100
After 6 years it will become 100 x 3 = 300
After 12 years it will become 300 x 3 = 900
After 18 years it will become 900 x 3 = 2700
After 24 years it will become 2700 x 3 = 8100
Which is 81 times of initial amount of 100.
Earlier I had calculated with mathematical formulae.
Hope it is now clear.
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