a sum of money become rs. 6500 after 3 years and 10562.50 after 6 years on compund interst. the sum is
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Answer:
Let the sum of Money be
′
P
′
.
A=P(1+
100
R
)
T
where R= Rate of Interest.
Amount after 3 years =6500
⇒6500=P(1+
100
R
)
3
⟶(I)
Amount after 6 years =10,562.5
⇒10562.5=P(1+
100
R
)
6
⟶(II)
From eq(I)
P
6500
=(1+
100
R
)
3
⇒(
P
6500
)
2
=(1+
100
R
)
6
⟶(III)
Putting eq(III) in eq(II)
10562.5=P(
P
6500
)
2
⇒10562.5=P×
P
2
(6500)
2⇒P=
10562.5
(6500)
2 =4000
Hence, the sum of 4000.
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