a sum of money become triple of itself in 8 years at simple intrest. so in tweleve years it will become how many times of itself at the same rate
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Let the sum of money be x
Time is 8 years
After 8 years it triples . So it becomes 3x.
So the simple interest is 3x-x=2x
Let the rate of interest be y.
So , x*y*8/100= 2x
Or,
y=200/8=25%
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Question:
A sum of money become triple of itself in 8 years at simple intrest. So, In tweleve years it will become how many times of itself at the same rate?
Answer:
Sum of money = x
After 8 years = 3x
Simple Interest = y%
⚫ In 8 years, the simple interest becomes the the sum of money in its triple form.
⚫ Then, In 12 years with the same Interest, the Money will be = ?
= In 8 years it changes in its triple form.
Then, in 4 years it will be changed to 1½ form.
= These show the multiples of 4 : 4, 8 and 12.
So,
4 = 1½ part
8 = 3 part
12 = 3 + 1½ part = 4½ part.........
Thus, In 12 years, It would be multiple its 4½ part.
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