a sum of money becomes 256/81 times of itself in 4 years compounded annually ,find rate of interest
give full explanation!!
Answers
➯ᴀɴs
❥ʀᴀᴛᴇ ᴏғ ᴛʜᴇ ɪɴᴛᴇʀᴇsᴛ ɪs 40%.
4:9
2:3
3-2 -: 1.
❥1/2 x 90 -: 40%.
■ ANSWER ■
A certain sum of money becomes 625/256 times of itself in 1 year. What is the rate of interest for annum if
Let P = Rs x. , A =Rs.(625/256).x. , T = 1year = 4 quarter. , rate of interest = r%
Let P = Rs x. , A =Rs.(625/256).x. , T = 1year = 4 quarter. , rate of interest = r%p.a. = r/4 % p.quarter.
Let P = Rs x. , A =Rs.(625/256).x. , T = 1year = 4 quarter. , rate of interest = r%p.a. = r/4 % p.quarter.A = P .(1 + r/100)^T.
Let P = Rs x. , A =Rs.(625/256).x. , T = 1year = 4 quarter. , rate of interest = r%p.a. = r/4 % p.quarter.A = P .(1 + r/100)^T.or, (625/256).x = x .(1+ r/400)^4.
Let P = Rs x. , A =Rs.(625/256).x. , T = 1year = 4 quarter. , rate of interest = r%p.a. = r/4 % p.quarter.A = P .(1 + r/100)^T.or, (625/256).x = x .(1+ r/400)^4.or, (5/4)^4 = (1+ r/400)^4.
Let P = Rs x. , A =Rs.(625/256).x. , T = 1year = 4 quarter. , rate of interest = r%p.a. = r/4 % p.quarter.A = P .(1 + r/100)^T.or, (625/256).x = x .(1+ r/400)^4.or, (5/4)^4 = (1+ r/400)^4.or, 5/4 = 1 + r/400.
Let P = Rs x. , A =Rs.(625/256).x. , T = 1year = 4 quarter. , rate of interest = r%p.a. = r/4 % p.quarter.A = P .(1 + r/100)^T.or, (625/256).x = x .(1+ r/400)^4.or, (5/4)^4 = (1+ r/400)^4.or, 5/4 = 1 + r/400.or, 5/4 - 1 = r/400.
Let P = Rs x. , A =Rs.(625/256).x. , T = 1year = 4 quarter. , rate of interest = r%p.a. = r/4 % p.quarter.A = P .(1 + r/100)^T.or, (625/256).x = x .(1+ r/400)^4.or, (5/4)^4 = (1+ r/400)^4.or, 5/4 = 1 + r/400.or, 5/4 - 1 = r/400.or, 1/4 = r/400.
Let P = Rs x. , A =Rs.(625/256).x. , T = 1year = 4 quarter. , rate of interest = r%p.a. = r/4 % p.quarter.A = P .(1 + r/100)^T.or, (625/256).x = x .(1+ r/400)^4.or, (5/4)^4 = (1+ r/400)^4.or, 5/4 = 1 + r/400.or, 5/4 - 1 = r/400.or, 1/4 = r/400.or, 4.r. = 400
Let P = Rs x. , A =Rs.(625/256).x. , T = 1year = 4 quarter. , rate of interest = r%p.a. = r/4 % p.quarter.A = P .(1 + r/100)^T.or, (625/256).x = x .(1+ r/400)^4.or, (5/4)^4 = (1+ r/400)^4.or, 5/4 = 1 + r/400.or, 5/4 - 1 = r/400.or, 1/4 = r/400.or, 4.r. = 400or, r = 400/4 = 100 % p.a. Answer.