Question

A sum of money becomes 4 times itself in 3
years at a simple interest. In how many years
will it amount to 7 times itself?​

Answer 1

Let principal be x

PRT/100=S.I
xR3/100=S.I. eq(1)

A=SI+P
4P=SI+P
SI=3P
SI=3x eq (2)

xR3/100=3x
R=100%

For 7 times SI=6x

SI=xRT/100
6x=x.100.T/100
T=6years

Answer 2

It takes 6 years to get amount to 7 times itself.

Step-by-step explanation:

Since we have given that

Let sum be P

Let amount be 4P

Interest = Amount - Sum = 4P - P = 3P

Time = 3 years

According to question, we get that

$3P=\dfrac{P\times R\times 3}{100}\\\\R=100\%$

If A = 7P

Simple = 7P - P = 6P

So, it becomes

$6P=\dfrac{P\times 100\times t}{100}\\\\t=6\ years$

Hence, it takes 6 years to get amount to 7 times itself.

# learn more:

A sum of money becomes 3 times of itself in 5 years. in how many years will it be 8 times under Simple interest ?

https://brainly.in/question/11771950