A sum of money becomes 5070 in 18 months and 5610 in 9\2 years. Find the principal,
the rate of interest, and the amount after 5 years.
Answers
Answered by
134
Given :-
⇛Amount after 18 months( A1 ) = ₹5070
⇛Time ( T1 ) = 18 months
⇛1 year = 12 months ( 3/2 years)
⇛Amount after 9/2 years ( A2 ) = ₹5610
⇛Time ( T2 ) = 9/2 years
To Find :-
⇛Simple interest
⇛Principal
⇛Rate of interest
⇛Amount after 5 years
Solution :-
A2 - A1
= ₹5610 - ₹5070
= ₹540
T2 - T1
∴ Simple interest( SI ) for 3 years = ₹540
SI for 3/2 years = 540/2
= ₹270
Hence, SI for 3/2 years is ₹270
Principal = A1 - SI
= ₹5070 - ₹270
= ₹4800
Hence , The Principal is ₹4800
Now, we will find rate of interest
Hence, The rate of interest is 3.75%
SI for 5 years :-
Hence , The simple interest is ₹900
Amount after 5 years = Principal + Simple interest
= 4800 + 900
= ₹5700
Hence , The Amount after 5 years is ₹5700
Answered by
6
Given :-
⇛Amount after 18 months( A1 ) = ₹5070
⇛Time ( T1 ) = 18 months
⇛1 year = 12 months ( 3/2 years)
⇛Amount after 9/2 years ( A2 ) = ₹5610
⇛Time ( T2 ) = 9/2 years
To Find :-
⇛Simple interest
⇛Principal
⇛Rate of interest
⇛Amount after 5 years
Solution :-
A2 - A1
= ₹5610 - ₹5070
= ₹540
T2 - T1
= \frac{9}{2} - \frac{3}{2}=
2
9
−
2
3
= \frac{6}{2}=
2
6
= 3 \: years=3years
∴ Simple interest( SI ) for 3 years = ₹540
SI for 3/2 years = 540/2
= ₹270
Hence, SI for 3/2 years is ₹270
Principal = A1 - SI
= ₹5070 - ₹270
= ₹4800
Hence , The Principal is ₹4800
Now, we will find rate of interest
\frac{PTR}{100} = 270(SI)
100
PTR
=270(SI)
\frac{4800 \times \frac{3}{2 } \times r }{100}
100
4800×
2
3
×r
72r = 27072r=270
r = \frac{270}{72}r=
72
270
r = \frac{15}{4}r=
4
15
r = 3.75\%r=3.75%
Hence, The rate of interest is 3.75%
SI for 5 years :-
\frac{4800 \times 5 \times 3.75}{100}
100
4800×5×3.75
= 900=900
Hence , The simple interest is ₹900
Amount after 5 years = Principal + Simple interest
= 4800 + 900
= ₹5700
Hence , The Amount after 5 years is ₹5700
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