a sum of money becomes 8 / 5 of itself in 5 years at a certain rate of simple interest find the rate of interest
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Answered by
36
HI , Let Principal = Rs P
Time ( T ) = 5 years
Amount ( A ) = Rs 8p/5
Let rate of interest = R
Simple interest ( I ) = A - P
I = 8p/5 - P
I = ( 8P - 5P )/5
l = 3P/5 ---( 1 )
We know that ,
I = ( PTR )/100 ---( 2 ) From ( 1 ) and ( 2 )
3P/5 = ( P × 5 × R )/100
( 3P × 100 )/( P × 5 × 5 ) = R
After cancellation ,
12 = R
Therefore ,
Rate of interest = R = 12%
I hope this helps you.
: )
Time ( T ) = 5 years
Amount ( A ) = Rs 8p/5
Let rate of interest = R
Simple interest ( I ) = A - P
I = 8p/5 - P
I = ( 8P - 5P )/5
l = 3P/5 ---( 1 )
We know that ,
I = ( PTR )/100 ---( 2 ) From ( 1 ) and ( 2 )
3P/5 = ( P × 5 × R )/100
( 3P × 100 )/( P × 5 × 5 ) = R
After cancellation ,
12 = R
Therefore ,
Rate of interest = R = 12%
I hope this helps you.
: )
Answered by
17
Let the principal be P
Amount = 8 /5
given T = 5 yrs
SI = A - P
A = 8 /5p
A = 8p / 5-p
SI = 3p -5
Again SI = prt / 100
3p /5 = prt / 100
3 / 5 = 5r / 100
R = 3*20 /5
R = 3 *4
R = 12
so interest is 12%
Amount = 8 /5
given T = 5 yrs
SI = A - P
A = 8 /5p
A = 8p / 5-p
SI = 3p -5
Again SI = prt / 100
3p /5 = prt / 100
3 / 5 = 5r / 100
R = 3*20 /5
R = 3 *4
R = 12
so interest is 12%
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