A sum of money becomes 8 times in 3 years then in how many years will the same sum become 27 times at the same rate of interest compounded annually
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Answered by
1
Solution 1 :-------
Let us consider the following;
Principal = P, Rate = R% per annum,
Time = T years and A = Amount due after 3 years
so,
Amount =P(1+R100)38P
=P(1+R100)38
=(1+R100)32
=1+R1001
=R100R
=100%
Solution 2 (using formula):---------
If a certain sum becomes n times in t years, then the rate of compound interest
=[n(1/t)−1]×100%
=[8(1/3)−1]×100%
=(2−1)×100%
=100%
Let us consider the following;
Principal = P, Rate = R% per annum,
Time = T years and A = Amount due after 3 years
so,
Amount =P(1+R100)38P
=P(1+R100)38
=(1+R100)32
=1+R1001
=R100R
=100%
Solution 2 (using formula):---------
If a certain sum becomes n times in t years, then the rate of compound interest
=[n(1/t)−1]×100%
=[8(1/3)−1]×100%
=(2−1)×100%
=100%
Answered by
0
Answer:
hope it will help you
Step-by-step explanation:
mine is the same
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