A sum of money becomes rs. 17280 in 2 years and rs. 20736 in 3 years at compound interest compounded annually. Find the sum.
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Answer:
The required sum = Rs.12,000
Step-by-step explanation:
P = initial amount
R = rate of interest per cent per year (annual compounding)
T = time period in years
A = final amount at the end of T years
A = P(1 + R/100)^T
ATQ,
A = 17280 when T = 2
=> 17280 = P(1 + R/100)^2 .........Eqn 1
Also
A = 20736 when T = 3
=> 20736 = P(1 + R/100)^3 .........Eqn 2
Dividing Eqn 2 by Eqn 1, we get:
(20736/17280) = [(1 + R/100)^3] / [(1 + R/100)^2]
1.2 = (1 + R/100)
(1 + R/100) = 1.2
R/100 = 0.2
R = 20
Substituting for R in Eqn 1,
17280 = P(1 + 20/100)^2
17280 = P(1.2)^2
17280 = P(1.44)
P = 17280/1.44
P = 12000
The required sum is Rs.12,000 and the rate of interest = 20% per year
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