Math, asked by alheafatima, 1 year ago

A sum of money becomes rs 17640 in two years and rs18522 in 3 years at the same rate of interest compounded annually.Find the sum and the rate of interest per annum?

Answers

Answered by yuvrajkj
60
The difference of two successive amounts must be the simple interest in 1 year on

the lower amount of money. 

S.I = 18522/- - 17640/- = Rs. 882/- 

Rate of interest = (882/17640) × (100/1) => 8820/1764 = 5% 

Principal = Amount/(1 + R/100)n 

= 17640/(1 + 5/100)2 

= 17640/(21/20 × 21/20) 

= 17640/(1.05 × 1.05) 

= 17640/1.1025 

= 16000

Thus the principal is Rs.16000/- and the rate of interest is 5%
Answered by archana2341976
13

Answer:The difference of two successive amounts must be the simple interest in 1 year on

the lower amount of money. 

S.I = 18522/- - 17640/- = Rs. 882/- 

Rate of interest = (882/17640) × (100/1) => 8820/1764 = 5% 

Principal = Amount/(1 + R/100)n 

= 17640/(1 + 5/100)2 

= 17640/(21/20 × 21/20) 

= 17640/(1.05 × 1.05) 

= 17640/1.1025 

= 16000

Thus the principal is Rs.16000/- and the rate of interest is 5%

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