A sum of money becomes rs. 4500 after two years and rs. 6750 after 4 years on compound interest. the sum is:
Answers
Answered by
6
time 1 = 2 year
amount(A2) =Rs 6750
time 2 = 4years
let the rate% =R%
Principal= Rs p
A/q
4500= p ( 1+R/100)² .......(i)
6750= p(1+R/100) power 4 .......(ii)
By adding equation (ii) by the equation...
6750/4500= (1+R/100)²...(iii)
From equation (i) & (ii)
4500= P*3/2
P = 4500*2/3
now we divide 4500 by 3 we get 1500
then 1500 *2=3000
we get principal =3000
and the C.I = 4500
amount(A2) =Rs 6750
time 2 = 4years
let the rate% =R%
Principal= Rs p
A/q
4500= p ( 1+R/100)² .......(i)
6750= p(1+R/100) power 4 .......(ii)
By adding equation (ii) by the equation...
6750/4500= (1+R/100)²...(iii)
From equation (i) & (ii)
4500= P*3/2
P = 4500*2/3
now we divide 4500 by 3 we get 1500
then 1500 *2=3000
we get principal =3000
and the C.I = 4500
Answered by
2
Answer:
Step-by-step explanation:
A) Rs. 4000
B) Rs. 2500
C) Rs. 3000
D) Rs. 3050
Correct Answer:
C) Rs. 3000
Description for Correct answer:
Amount(A1) = Rs.4500,
t1= 2 years
Amount(A2) = Rs.6750,
t1= 4 years
Let the Rate % = R %
Principal = Rs. P
According to the question,
Case1: 4500
=p(1+R100)2...........1
Case2: 6750
=p(1+R100)4...........1
By dividing eq. 2, by eq. 1
67504500=(1+R100)2
32=(1+R100)2..........3
From eq. 1
4500=P×32
P= Rs.3000
Hence,Required principal
=Rs. 3000
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