Question

A sum of money becomes Rupees 6615 at a compound interest rate of 5% per annum in 2 years. Find the principal at the beginning of the second year .​

Answer 1

Answer:

$a = p(1 + \frac{r}{100} )^{t} \\ 6615 = p(1 + \frac{5}{100} ) ^{2 } \\ 6615 = \frac{441p}{400} \\ 441p = 400 \times 6615 \\ p = \frac{400 \times 6615}{441} \\ p = 6000 \\ anssssss$

Step-by-step explanation:

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Answer 2

Answer:

I am giving u the process u can find the answer

Step-by-step explanation:

P(1+r/100)n^

or

PxRxT/100

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