Math, asked by worknehtesfaye, 18 hours ago

. A sum of money deposited at compound interest amounts to Birr 8820 in two years and Birr 9261 in 3 years find the rate of interest compounded annually
A) 6% B) 1 0.5% C) 4.5% D) 5% E) 1 0%

Answers

Answered by mathdude500
8

 \green{\large\underline{\sf{Solution-}}}

Let us assume that

  • Sum deposited = Rs p

  • Rate of interest = r % per annum compounded annually.

We know that,

Amount on a certain sum of money of Rs p invested at the rate of r % per annum compounded annually for n years is

 \red{\boxed{\tt{Amount \:  =  \: p {\bigg[1 + \dfrac{r}{100} \bigg]}^{n} \: }}}

So, According to statement

A sum of money deposited at compound interest amounts to Birr 8820 in two years.

\rm :\longmapsto\:8820 = p {\bigg[1 + \dfrac{r}{100} \bigg]}^{2} -  -  - (1)

According to second condition

A sum of money deposited at compound interest amounts to Birr 9261 in three years

\rm :\longmapsto\:9261 = p {\bigg[1 + \dfrac{r}{100} \bigg]}^{3} -  -  - (2)

On dividing equation (2) by equation (1), we get

\rm :\longmapsto\:\dfrac{9261}{8820}  = \dfrac{p {\bigg[1 + \dfrac{r}{100} \bigg]}^{3} }{p {\bigg[1 + \dfrac{r}{100} \bigg]}^{2}}

\rm :\longmapsto\:\dfrac{441}{420}  = 1 + \dfrac{r}{100}

\rm :\longmapsto\:\dfrac{21}{20}  = 1 + \dfrac{r}{100}

\rm :\longmapsto\:\dfrac{21}{20} - 1  =  \dfrac{r}{100}

\rm :\longmapsto\:\dfrac{21 - 20}{20} =  \dfrac{r}{100}

\rm :\longmapsto\:\dfrac{1}{20} =  \dfrac{r}{100}

\bf\implies \:r \:  =  \: 5 \: \%

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Additional Information :-

1. Amount on a certain sum of money of Rs p invested at the rate of r % per annum compounded semi - annually for n years is

 \red{\boxed{\tt{Amount \:  =  \: p {\bigg[1 + \dfrac{r}{200} \bigg]}^{2n} \: }}}

2. Amount on a certain sum of money of Rs p invested at the rate of r % per annum compounded quarterly for n years is

 \red{\boxed{\tt{Amount \:  =  \: p {\bigg[1 + \dfrac{r}{400} \bigg]}^{4n} \: }}}

3. Amount on a certain sum of money of Rs p invested at the rate of r % per annum compounded monthly for n years is

 \red{\boxed{\tt{Amount \:  =  \: p {\bigg[1 + \dfrac{r}{1200} \bigg]}^{12n} \: }}}

Answered by thakrepayal
3

Given:

A sum of money deposited at compound interest amounts to Birr 8820 in two years and Birr 9261 in 3 years

Find:

Find the rate of interest compounded annually.

Let us assume that

Sum deposited = Rs p

Rate of interest = r % per annum compounded annually.

We know that,

Amount on a certain sum of money of Rs p invested at the rate of r % per annum compounded annually for n years is

Amount=p[1+\frac{r}{100} ]^{n}

So, According to a statement

A sum of money deposited at compound interest amounts to Birr 8820 in two years.

8820=p[1+\frac{r}{100} ]^{2}----1)

According to the second condition

A sum of money deposited at compound interest amounts to Birr 9261 in three years

9261=p[1+\frac{r}{100} ]^{3}----2)

On dividing equation (2) by equation (1), we get

\frac{9261}{8820} =\frac{p[1+\frac{r}{100} ]^{3}}{p[1+\frac{r}{100} ]^{2}} \\

\frac{441}{420}=1+\frac{r}{100}

\frac{21}{20}=1+\frac{r}{100}

\frac{21}{20}-1=\frac{r}{100}

\frac{21-20}{20}=\frac{r}{100}

\frac{1}{20}=\frac{r}{100}

r=5%%

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