Question

a sum of money double is itself in 4 years in how many years it will become 8th times ​

Answer 1

Answer:

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Answer 2

100Amount=Rs. 200Rate=r%Time=4yearsNow,A=P×[1+(r100)]n200=100×[1+(r100)]42=[1+(r100)]4−−−−−−(i)Ifsumbecome8timesinthetimenyearsthen,8=(1+(r100))n23=(1+(r100))n−−−−−−(ii)Usingeqn(i)in(ii),weget([1+(r100)]4)3=(1+(r100))n[1+(r100)]12=(1+(r100))nThus,n=12years.