Math, asked by kundanraj61, 1 year ago

A sum of money doubles it self in 7 years. In how many years will it become four fold​

Answers

Answered by Xeolem
1

If compound interest is used, then, as per the question, in 7 years

A=2P

⟹P{1+R100}7=2P

⟹{1+R100}7=2

⟹{1+R100}=217 ....(1)

Now, for the principal to quadruple,

A=4P

⟹P{1+R100}t=4P

⟹{1+R100}t=4

Now substituting (1) in the above expression we get,

{217}t=4

⟹2t7=4

Taking log of both sides, we get

t7×log(2)=log(4)

⟹t7=log(4)log(2)=2

⟹t=2×7=14 years (which is quite intuitive)

Where,

P = principal

R = rate of interest (p.a.)

t = time (years)

A = amount


Xeolem: ek bar batao
Xeolem: main edit krunga
kundanraj61: Hum book me ans dekha hai
Xeolem: oo
Xeolem: are 21 bhi ho skta h
Xeolem: vaise 14 bhi hoga
kundanraj61: Kaisa hoga batiya
Xeolem: Answer = 21
Xeolem: For eg. You have 5rs. It doubles in 7year, It means 5rs is added. Now, 5+5=10rs. After, 14 years, 5 is again added. Now, You have 10+5=15. After, 21 years 5 is again added. Now, You have 15+5=20. So it 4x in 21 years.
Xeolem: So, After 7 years the money is added.
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