Math, asked by rohitatlas97797, 9 months ago

A sum of money doubles itself at C.I in 15 years . In how many years it will become eight times​

Answers

Answered by Anonymous
3

Step-by-step explanation:

2x = x * ( 1 + R/100 )^15

2 = ( 1 + R/100 )^15 ------(1)

8x = x * ( 1 + R/100 ) ^n

8 = ( 1 + R/100)^n

(2)³ = ( 1 + R/100)^n

{( 1 + R/100 )^15}³ = ( 1 + R/100 )^n

( 1 + R/100 )^45 = ( 1 + R/100)^n

n = 45 years

So , In 45 years , The money will become 8

times.

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