Question

A sum of money doubles itself in 10 years the number of years it would triple itself is

Answer 1

Answer:

In 20 years amount will be tripled.

Step-by-step explanation:

let x be the amount

In First Case:

P = x

T = 10 years

A = 2x

SI = 2x - x = x

Using SI formula,

$SI=\frac{P\times R\times T}{100}$

$x=\frac{x\times R\times10}{100}$

R = 100/10 = 10 %

Second Case:

when amount is tripled,

we have A = 3x

P = x

R = 10 %

SI = 3x - x = 2x

We have to find Time , T

$SI=\frac{P\times R\times T}{100}$

$2x=\frac{x\times10\timesT}{100}$

T = 2 × 10

T = 20

Therefore, In 20 years amount will be tripled.

Answer 2

Answer:

20 years

Step-by-step explanation:

frist step:

let A=2x , p=x

s.i=a-p

s.i=2x-x

s.i=x

s.i=prt/100

x=x*r/100*10

r=10%

second step :

a=3x , p=x , r=10%

s.i = 3x-x=2x

2x=x*10/100*t

t=2*10

t=20 years

hope it is helpful