Question

A sum of money doubles itself in 10 years.the number of years it would triple itself is

Answer 1

I think the answer of this question is 20 years

Answer 2

Answer:

In 20 years amount will be tripled.

Step-by-step explanation:

Given that a sum of money doubles itself in 10 years.

we have to find the number of years it would triple itself.

Let x be the sum  of money

Case 1: A sum of money doubles itself in 10 years.

Principal, P = x  

Time, T = 10 years

Amount, A = 2x

$SI = Amount-Principal=A-P=2x - x = x$

By simple interest formula,

$SI=\frac{P\times R\times T}{100}$

$x=\frac{x\times R\times10}{100}$

$R = \frac{100}{10}= 10\%$

Case 2: when amount is tripled,

Amount, A = 3x

P = x

R = 10%

$SI = Amount-Principal=A-P=3x - x = 2x$

we have to find Time , T

$S.I=\frac{P\times R\times T}{100}$

$2x=\frac{x\times10\timesT}{100}$

$T=2\times 10=20yrs$

∴ In 20 years amount will be tripled.