Question

a sum of money doubles itself in 8 years. What is the rate of intrest

Answer 1

Hello


Here is your answer


Let the principle be Rs.x
Amount=Rs.2x
Time =8years
$a = p(1 + \frac{tr}{100})$
$2x = x(1 + \frac{8r}{100})$
$2x = x( \frac{100 + 8r}{100})$

2(100)=100+8r
200-100=8r
100=8r
$r = \frac{100}{8}$
r=12.5%


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Answer 2

• Let the Principle be Rs.x.
• Then amount = 2 x .
• So SI = A -P = 2 x - x =  Rs .x
• Time = 8 years.

Rate = (SI x 100)/( P x T)

               =   (x × 100)/(x × 8)

                = 100 x /8 x = 100/8 = 25/2

                     = 12 1/2 %

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