A sum of money doubles itself in 8 years. what is the rate of interest?
Answers
Answered by
211
Principal =Rs.x
Amount=Rs.2x
Time=8 years
Amount=Principal+Simple interest
2x=x+SI
2x-x=SI
SI=x
Simple interest=PTR/100
x=(x×8×R/100)
x=8xR/100
x×100/8x =R
R=100/8
R=12.5%
Hence Rate of interest=12.5%
Amount=Rs.2x
Time=8 years
Amount=Principal+Simple interest
2x=x+SI
2x-x=SI
SI=x
Simple interest=PTR/100
x=(x×8×R/100)
x=8xR/100
x×100/8x =R
R=100/8
R=12.5%
Hence Rate of interest=12.5%
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Answered by
72
Step-by-step explanation:
p=x
Amount=2x
t=8 yrs
amount=p+SI
2x=X+SI
SI=x
SI=ptr/100
x=(X*8*r/100)
X*100/8x=R
R=100/8
R=12.5
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