Question

A sum of money invested at 8% per annum amounts to ₹12122 in 2 years . What will it amount to in 2 years 8 months at 9% per annum?


P- 12122,T- 2years,R-8%


what is the soluetion ?


needing correct answer and soluetion ​

Answer 1

SI=100P×r×t

12122=100P×8×2

12122=100P×116P=Rs.10,450.

Now, for t=232,r=9%

SI=100P×r×t

SI=10010450×9×(8/3)=2058

Amount P+SI=10450+2058=Rs.12,958.

Answer 2

Amount :- 12122 Rs.

Rate :- 8%

Time :- 2 years

Let principal = x

Then,

⠀ ⠀⠀12122 - x = $\frac{x \times 8 \times 2}{100} [\tex]</p><p></p><p>=> 12122 = [tex]\frac{29x}{25}$

=> 12122 x $\frac{25}{29}$ = x

=> 418 x 25 = x

=> 10450 = x

After 2 years 8 month at 9% per annum

Time :- $\frac{8}{3}$ years

Rate :- 9%

Principal :- 10450

Interest :- $\frac{10450 \times 8 \times 9}{300}$

=> $\frac{10450 \times24}{300}$

=> $\frac{250800}{100}$

=> 2508 Rs.

Amount :- 10450+2508 => 12958 Rs. Ans.