Question

a sum of money invested at 8% per annum for simple interst amounts to 12122 in 2 years what will it in 4 years rupees ​

Answer 1

$\bf\large\underline\pink{Solution :-}$

P = x

R = 8%

T = 2 years

SI = P * R * T / 100

= x * 8 * 2 / 100

= 4x / 25

A = P + SI

= x + 4x / 25

= 29x / 25

But Amount = ₹ 12122

29x / 25 = 12122

x = 12122 * 25 / 29

= ₹ 10450

To find the amount after 2 years 8 months

P = ₹ 10450

R = 9%

T = 2 years 8 months

= 8/3 years

SI = P * R * T / 100

= 10450 * 9 * 8 / 100 * 3

= ₹ 2508

A = P + SI

= 10450 + 2508

= ₹ 12958

Answer 2

Answer:

P = x

R = 8%

T = 2 years

SI = P * R * T / 100

= x * 8 * 2 / 100

= 4x / 25

A = P + SI

= x + 4x / 25

= 29x / 25

But Amount = ₹ 12122

29x / 25 = 12122

x = 12122 * 25 / 29

= ₹ 10450

To find the amount after 2 years 8 months

P = ₹ 10450

R = 9%

T = 2 years 8 months

= 8/3 years

SI = P * R * T / 100

= 10450 * 9 * 8 / 100 * 3

= ₹ 2508

A = P + SI

= 10450 + 2508

= ₹ 12958