Question

A sum of money invested at a certain rate of simple interest doubles itself in 10
years. In how much time will it treble itself at the same rate?​

Answer 1

ANSWER:

Step by step explanation;

Since sum double itself in 10 years, so sum

= S.I. for 10 years.

Let sum = x.

Then,

S.I. = x and TIME = 10 years

$rate \: = (\frac{100}{x} \times \frac{x}{10})\% = 10\%$

Now, sum = x, S.I. = 2x, Rate = 10%

$time = ( \frac{100}{x} \times \frac{2x}{ 10} )years \:$

= 20 years.

ANSWER By ARYAN