Question

A sum of money invested at compound interest amounts to 2,210 in 3 years and 2.276.30 in 4 years. The
interest p.a., interest compounded annually, is:
N​

Answer 1

Answer:

$\huge \sf {\orange {\underline {\pink{\underline {Answer}}}}}$

Let Principal as “P”.

As we know that,

Formula to finding amount is -

Amount = ( 1 + r/100^n )

Here,

Amount = ₹ 5445

Principal = P

Rate of interest = 10%

Time = 10 year's

Substituting the value,

5445 = P × ( 1+ 10/100 )²

5445 = P × ( 100 + 10/100 )²

5445 = P × ( 110 /100 )²

5445 = P × ( 11 /10 )²

5445 = P × ( 11 × 11 / 10 × 10 )

5445 = P × 121 / 100

P = 5445 × 100 / 121

P = 45 × 100

P = 4500

Answer = 4500

Hence, Principal = 4500

Answer 2

Answer:

Let Principal as “P”.

As we know that,

Formula to finding amount is -

Amount = ( 1 + r/100^n )

Here,

Amount = ₹ 5445

Principal = P

Rate of interest = 10%

Time = 10 year's

Substituting the value,

5445 = P × ( 1+ 10/100 )²

5445 = P × ( 100 + 10/100 )²

5445 = P × ( 110 /100 )²

5445 = P × ( 11 /10 )²

5445 = P × ( 11 × 11 / 10 × 10 )

5445 = P × 121 / 100

P = 5445 × 100 / 121

P = 45 × 100

P = 4500

Answer = 4500

Hence, Principal = 4500