Question

a sum of money invested at compound interest amounts. to 19360 in. 2years and to23425.60 in 4. years . find the rate percent and. the. original sum of. money



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Answer 1

the answer of this question is rupees 9680 hope it help

Answer 2

Answer:

The sum of Money=16000

The Rate=10%

Step-by-step explanation:

Let the sun of money = P , The Rate=R

So, according to the question,

p$P(1+\frac{R}{100})^{2}  = 19360$

=> $P(\frac{100+R}{100})^2=19360$

=>$P=19360 *(\frac{100}{100+R})^2$  ....(1)

Also,

$P(1+\frac{R}{100})^4=23425.60$

=>$P(\frac{100+R}{100})^4=23425.60$

from eqn.2

$19360*(\frac{100}{100+R})^2*(\frac{100+R}{100})^4=23425.60$

=>$\frac{1936(100+R)^2}{1000}=23425.60$

=>$(1936(100+R)^2=23425600$

Taking Square roots of both sides,

$44(100+R)=4840$

=>$100+R=110$

=>$R=10$

From Eqn.2

$P=19360*(\frac{100}{100+R})^2$

=>$P=16000$

Hope this Helps you,

Omkesh