A sum of money invested at compound interest of 8% p.A, compounded annually amounted to ₹7290 in two years. Find the sum invested.
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Let PRINCIPAL as “P”.
Amount = ( 1 + r/100^n )
Amount = ₹ 5445
Principal = P
Rate of interest = 10%
Time = 10 year's
Substituting the value,
5445 = P × ( 1+ 10/100 )²
5445 = P × ( 100 + 10/100 )²
5445 = P × ( 110 /100 )²
5445 = P × ( 11 /10 )²
5445 = P × ( 11 × 11 / 10 × 10 )
5445 = P × 121 / 100
P = 5445 × 100 / 121
P = 45 × 100
P = 4500
Answer = 4500
Hence, Principal = 4500
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