A sum of money invested at compound intrest doubles itself in4yrs intrest being payable annually. In how much time will it be eight times. plzz explain
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The formula for such questions of compound intrest is,
A=[P(1 + r/n)^nt] -P
Where A is Amount, P is Principle, r is Rate of Intrest, t is Time and n is number of times the intrest is compounded per t.
Let the principle here be x.
t is 1 year.
For 4 years, n1=4.
For x years, n2=8.
I am using a different formula to make it easier, n2=n1^(t2/t1)
Putting the values in it,
8=4^(x/4)
2^3=2^2(x/4)
Thus,
3=2(x/4)
12=2x
x=6
Thus the intrest will be 8 times in 6 years.
You can use the aforementioned formal as well.
4p=p(1+r/100)^4
Thus
4=(1+r/100)^4
For x years,
8=(1+r/100)^n
Which gives us again 6 years.
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