Question

. A sum of money invested at simple interest 13 times itself in 19 Years.

How many times will it become in 76 years​

Answer 1

Answer:

Step-by-step explanation:

Let the sum of money be 100 rupees.

In seven years it becomes 5 times. Therefore,

100×5=500 in seven years.

Now According to simple interest formula.

A=P(1+rt)

Where A= final amount

P= Principle amount

r= rate.

t= time

Now on putting the values and solving it we get

500=100(1+7r)

From this equation we get r= 0.5714 or 57.14%

Now putting the values in the equation again to solve for the number of years required to get the initial amount multiplied 25 times.

2500=100(1+57.14t)

After solving the equation we get t= 42. And it is the answer of the problem