Question

a sum of money invested with simple interest amount to rupees 23400 in 5 years and to Rupees 26640 in 8 years find the sum of money and the rate of interest​

Answer 1

Answer:

3 yrs interest=26640-234oo =324o

lyear interest =3240/3 = 1080

5yr, interest = 5400

principal =234oo-54oo=18ooo

sum=Rs 18000. Ans

R = 100x1080/18000x1=6% Ans

Answer 2

The principal and Rate of interest is Rs.18000 and 6% respectively.

Step-by-step explanation:

Let the principal be x

Case 1:

a sum of money invested with simple interest amount to rupees 23400 in 5 years

Amount = 23400

Time = 5 years

Simple interest = Principal - Interest = 23400-x

Formula :$SI = \frac{P \times T \times R}{100}$

$23400-x= \frac{x \times 5 \times R}{100}$

$\frac{100(23400-x)}{x \times 5}=R$ ---1

Case 2:

a sum of money invested with simple interest amount to rupees 26640 in 8 years

Amount = 26640

Time = 8 years

Simple interest = Principal - Interest = 26640-x

Formula :$SI = \frac{P \times T \times R}{100}$

$26640-x = \frac{x \times 8 \times R}{100}$

$\frac{100(26640-x )}{x \times 8}=R$ --- 2

Equate 1 and 2

$\frac{100(23400-x)}{x \times 5}=\frac{100(26640-x )}{x \times 8}$

$x=18000/tex]</p><p>Substitute the value of x in 1 </p><p>[tex]\frac{100(23400-x)}{x \times 5}=R$

$6\%=R$

Hence The principal and Rate of interest is Rs.18000 and 6% respectively.

#Learn more:

A certain sum of money amounts to Rs 23400 in 3 years at 10% per annum simple interest.Find the amount of the same sum in 2 years and at 10% p.a. compound interest.

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